Question

Divide 90 into two parts such that double of the first part exceeds three times the second part by 30. (answer quick pls)

Answer 1

Let the first part be x & second be y

According to question.,

2x = 3y + 30

2x - 3y = 30 ... ... (i)

x + y = 90 ... ... (ii)

3(ii) + (i)

2x - 3y = 30

3x + 3y = 270

On solving it...

5x = 300x = 60

Therefore, first part = x = 60

second part = y = 30

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Answer 2

Let first part be x and second part be y

x+y=90 therefore x=90-y

2x=3y+30
Substituting value of x

2(90-y)=3y+30

180-2y=3y+30

180-30=5y

150=5y

y=30

Therefore x= 90-30 = 60

First part = 60
Second part = 30

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