Divide 900 into two parts such that 60% of one part exceeds 30% of the other by 270.
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Next, it's given that \[30\% \] of other parts is to be found. So, as it is given in the question that \[60\% \] of one part exceeds \[30\% \] of the other by\[270\]. Hence, the value of two parts in which 900 is divided is 600 and 300
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