Math, asked by pujaraprathit, 7 months ago

Divide 9350 into three parts in such a way that half of the first part, one third of second part and and one sixth of the third part are equal. Please answer it.

Answers

Answered by saranshgaurn
7

Answer:

The 3 parts at 1,700, 2,550 and 5,100.

Step-by-step explanation:

x = the first part

y = the second part

z = the third part

x + y + z = 9,350

x/2 = y/3 = z/6

6(x/2 = y/3 = z/6)

3x = 2y = 1z

x = 2/3y

z = 2y

2/3y + y + 2y = 9,350

3 2/3y = 9,350

11/3y = 9,350

y = 2,550

x = 2/3y = 2,550 x 2/3 = 1,700

z = 2y = 2 x 2,550 = 5,100

1,700 + 2,550 + 5,100 = 9,350

The 3 parts at 1,700, 2,550 and 5,100.

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