Math, asked by anuragsharmamba, 6 months ago

divide 9p^3+6p^2-4p+6 by 3p+p^2-1​

Answers

Answered by pukultanvi4444
3

Answer:

9p3+6p2−4p+6/3p+p2−1

=9p3+6p2+−4p+2p+p2+−1

Combine Like Terms:

=9p3+6p2+−4p+2p+p2+−1

=(9p3)+(6p2+p2)+(−4p+2p)+(−1)

=9p3+7p2+−2p+−1

Step-by-step explanation:

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Answered by himanshubidhudi094
0

Answer:

divide the following and verify the result (9p³+6p²-4p+6)by (3p+p²-1)

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