Question

Divide

(9x^3 + 3x^2 - 5x + 7) by (3x - 1)

please solve this question in a piece of paper and attach it in the answers....​

Answer 1

Answer:

Q-3x2+2x-1

R-6

is your correct answer

Answer 2

According to me the answer is -

by using remainder theorem -

9x^3 + 3x^2 - 5x + 7 ÷ 3 x-1

3x - 1 = 0

3x = 1

x = 1/3

p ( x ) = 1/3 in 9x^3+3x^2 - 5x + 7

9×1/3 ×1/3 ×1/3 +3×1/3 ×1/3 - 5×1

/3 +7

= 1/3 + 1/3 - 5/3 + 7

= 2/3 +16/3

= 18 /3

= 6

this is the answer .....

hope it helps you......