Question

divide 9x^4- 8 x^ 3 - 12 x + 3 by 3 x


PLS answer this ​

Answer 1

Answer:

$\frac{ {9x}^{4} - - {8x}^{3} - 12x + 3} { {3x}^{} } \\ = \frac{ {9x}^{4} } {3x} - \frac{ {8x}^{3} }{3x} - \frac{ {12x}^{} }{3x} + \frac{ {3}^{} }{3x} \\ = {3x}^{3} - \frac{8}{3} {x}^{2} - 4 + \frac{1}{x}$

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