Divide 9x - 6x2 + x3 - 2 by (x - 2) and hence verify the division algorithm.
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Answered by
9
Answer:
x-2)x³-6x²+9x-2(x²-4x+1
-(x³-2x²)
___________
-4x²+9x-2
-(-4x²+8x)
_______________
x-2
-(x-2)
______________
0
_______________
quotient = q(x)=x²-4x+1
remainder =r(x)=0
divisor =g(x)=x-2
dividend =g(x)×q(x)+r(x)
x³-6x²+9x-2=(x-2)(x²-4x+1)+0
x³-6x²+9x-2=x³-6x²+9x-2
Answered by
3
x² -4x +1 is the quotient
and
0 is the remainder
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