Question

divide
a. 4y³ + 8y²-6y by 4y
​

Answer 1

$\frac{4 {y}^{3} + 8 {y}^{2} - 6y }{4y} \\ \\ \frac{2y(2 {y}^{2} + 4y - 3)}{4y} \\ \\ \frac{2 {y}^{2} + 4y - 3}{2}$