Question

divide a^8 - b^8 by a^2 + b^2


reply fast don't waste ur time and mine too! ​

Answer 1

Solution:

(a^8 - b^8)/(a^2 + b^2)

Factor
(a^8 - b^8) = (a^4 + b^4) (a^4 - b^4)

Since both terms are perfect squares, factor using the difference of squares formula,

= (a^4 + b^4) (a^4 - b^4)

= (a^4 + b^4) (a^2 - b^2) (a^2 + b^2)

= (a^4 + b^4) (a^2 - b^2) (a^2 + b^2)/(a^2 + b^2)

Cancel out the common,

= (a^4 + b^4) (a^2 - b^2)

= (a^4 + b^4) (a - b) (a + b)

Therefore, the factor is = (a^4 + b^4) (a - b) (a + b)

Hope this will help.