Math, asked by younghoonie, 1 day ago

divide:

a) 84xy²z³ by 7yz²

b)20(x²yz + xz²y + xy²z) by 5xyz

Answers

Answered by ananyasebastian903

0

Answer:

a) 84xy²z³/7yz²

= take 7yz outside since it's common in both cases

= 7yz(12xyz²)/7yz(z)

= 12xyz²/7yz

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