Question

divide a given line segment internally in the ratio 3:5 also write the steps of construction


​

Answer 1

Answer:

where is ur segment please mention it

Answer 2

Answer:

Step-by-step explan

​Let AB be our given line segment.

To construct:

Divide AB in the ratio of 3 : 5.

Steps of construction

1) Draw   AB

2) Draw   AX , making an acute angle with AB.

3) Locate 8(= 3 + 5) points A1  ,A2  ,A3 ,A4,A5 ,A6,A7and A8 on AX

so that AA1  =A1A2=A2A3=A3A4=A4A5=A5A6=A6A7=A8A9

4) JOIN B A8

5) Through the point A3 draw line parallel A8B

​(By making an angle equal to ∠AA8B) at A3  intersecting AB at the point C.

Then AC : CB = 3 : 5.