Question

divide a land having an area of 486m^2 in 3 parts such that half of the first part, one third of the second part and one fourth of third part are all equal.​

Answer 1

Answer:

Step-by-step explanation:

Let the parts be a, b, c. So, a/3=b/4=c/2

a= 3c/2

b=2c

Now, a+b+c= 486

or, 3c/2+2c+c= 486

or, 3c/2+3c= 486

or, 9c= 972

or, c= 108

So, b= 2c= 216 and a= 3c/2= 162