Question

Divide a line segment AB = 6cm in ratio 4:3 internally​

Answer 1

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Steps :

Step 1 : Draw a line segment AB = 6cm

Step 2 : Draw rays AQ and BP parallel to each other and on opposite side of AB

Step 3 : Mark 4+3 = 7 points on AQ and 7 on BP at equal distances, namely A1, A2, ___ A7 on AQ and B1,B2,___B7 on BP

Step 4 : Join A7 to B and B7 to A

Step 5 : Join A4 to B3 intersecting AB at C

Step 6 : Thus,C divides AB internally in ratio 4:3

Answer 2

We have to divide a line segment of length 6cm in the ratio 4:3.

Draw a line segment AB of length= 6cm

Now draw a ray X from A which makes an acute angle <XAB.

We need to divide the line segment in the ratio 4:3 internally.

Hence, we need to make 4+3= 7 equal parts.

On the ray AX, using a scale mark 7 equally distanced points.

Let the points be A1, A2, A3, A4, A5, A6, A7.

Join A7 and B using a scale.

The line segment should be in 4:3 ratio. Therefore at A4 draw a line parallel to the line BA7. It divides the line segment AB at C.

The line segment will be divided in the ratio 4:3

Checking:

$4 \times x +3 \times x = 6 \\ 7x = 6 \\ x = 6 \div 7 \\ x = 0.8cm$

If the line segment AB is divided as AC: CB in the ratio 4:3

AC= 4x

AC =4(0.8)

AC =3.2cm

Now, CB= 3x

CB=3(0.8)

CB=2.4cm

After drawing, using the above method, check whether the line is divided in 3.2+ 2.4 cm