Math, asked by paramubalu1988, 7 months ago

divide a polynomial by a monomial (z3-3z2+z) ÷z​

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Answered by hansdaraj17
0

Answer:

Divide the following polynomial by monomial. 2,3z^4-1 ... 3x-x31-3x2+3y-y31-3y2 +3z-z31-3z2=(3x-x31-3x2)(3z-z31-3z2)(3y-y31 -3y2)) ... The minimum value of |2z-1|+|3z-2| is.

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