Question

divide a rope 168m long into two parts such that one part may be 3/5of the other. ​

Answer 1

Let one part of rope be X mEo the other part is 3/5 X m

Answer 2

$total \: length \: = 168m \\ \\ first \: part \: has \: given \: = \frac{3}{5} \\ \\ first \: \: part \: length \: = 168 \times \frac{3}{5} = 100.8 \: meter \\ \\ second \: part \: length \: = 168 - 100.8 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 67.2 \: meter$