Question

divide a rope of length 560 cm into 2 parts such that twice the length of the smaller part is equal to 1/3 of the larger part then find the length of the larger part​

Answer 1

Answer:

Let 'x' Be The Smaller Number and 'y' Be The Larger Number

ATQ;

y/3 = 2x

=> y = 6x ----------(i)

We Know That;

x+y = 560cm

From Equation (i)

x+6x = 560

7x = 560

x = 80 cm

So Smaller Size Will Be 80cm and Larger Side Will Be 480 cm.

Answer 2

Answer:

let the smaller part of the robe be x cm and let the bigger part of the robe be y cm.

According to the 1st condition,

$x + y = 560...1)$

According to the 2nd condition,

$2x = \frac{1}{3} \: y$

$6x = y \\ 6x - y = 0...2)$

Adding equation 1 and 2,

$x + y = 560 \\ 6x - y = 0 \\ = 7x = 560$

$x = \frac{560}{7}$

x=80

Substituting x=80 in equation 1,

$x + y = 560 \\ 80 + y = 560 \\ y = 560 - 80 \\ y = 480$

Answer: The smaller part of the robe is of 80 cm and the bigger part of the robe is of 480 cm.