Question

Divide a rope of length 560 cm into 2 parts such that twice the length of the smaller part
is equal to
1
/3 of the larger part. Then find the length of the larger part.

Answer 1

Step-by-step explanation:

let the smaller part be x cm and largerpart be y cm

x+ y= 560. (1)

twice the length of the smaller part is equal to 1/3 of the larger part

2x= 1/3y

6x = y

putting the value of y in (1) we have

x+6x = 560

7x= 560

x= 80

and thus ,y= 6× 80= 480

thus, the larger part = 40 cm and smaller part is 80cm

Answer 2

Answer:

Let the smaller part be - x

then the second part - 560 - x

Now, according to the question :-

2x = 1/3(560- x)

2x = 560/3 - x/3

6x = 560 - x

6x + x = 560

7x = 560

x = 80

so, smaller part = 80cm

larger part = (560 - 80) =480cm

Step-by-step explanation:

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