Question

divide a rope of length 560 cm into 2 parts such that twice the length of a smaller part is equal to ⅓ of the Larger part . then find the length if the large part

Answer 1

let the smaller part be - x
then the second part - 560 - x
Now, according to the question :-
2x = 1/3(560- x)
2x = 560/3 - x/3
6x = 560 - x
6x + x = 560
7x = 560
x = 80
so, smaller part = 80cm
larger part = (560 - 80) =480cm

Answer 2

Let the length of smaller part be x cm nd the length of longer part will be 560-x....
According to the ques
2x=1/3(560-x)
6x=560-x
6x+x=560
x=80

Longer part=560-x=480cm