Question

Divide a rope of length 560 cm into 2 parts such that twice the length of the smaller part is equal 1/3 of the larger part . Then find the length of the larger part

Answer 1

Answer:-

Let the length of smaller part be x

So length of larger part will be 560-x

Given that

2 (x)=1/3 (560-x)

6x=560-x

7x=560

X=80

So length of larger part will be 560-x

That is 560-80 =480...

Therefore length of larger part is 480

Answer 2

Step-by-step explanation:

let the smallerpart be x cm

largest part be y cm

x+ y = 560. (1)

twice the length of the smaller part is equal to1/3 of the largest part

2x = 1/3 y

6x= y

putting the value of y in (1) we have

x+6 x = 560

7x= 560

x= 80

and thus, y= 6× 80= 480

thus,the larger part = 40 cm and smaller part is 80 cm