Question

divide a triangle into 3 equal parts​

Answer 1

Method I: After trisecting one side of a triangle (side BC below), connect the opposite vertex (point A) to the two points that trisect the side (H and I). Because the side is divided into three equal segments, all three triangles have the same length of base and height. Thus, all three triangles are of equal area.

Method II: In many ways, method II is simply a variation of method I. After trisecting one side of a triangle, construct a segment connecting the opposite vertex (point A) to only one of the points trisecting the side (I). We then have two triangles. One (ABI) is equal to 1/3 the area of the original triangle (ABC). The other triangle (AIC) is 2/3 the area of the original triangle (ABC)

Method III:

Another way to divide a triangle into three triangles of equal area is to find the centroid (the point where the medians intersect). After determining the centroid (point G below), construct the segments connecting the vertices to the centroid. The three triangle created are of equal area.