Math, asked by nganthoibi3621, 10 months ago

divide (am²+bm²-bn²-an²)÷(m+n)

Answers

Answered by rahuljaiswal2002
4

Answer:

Step-by-step explanation:

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Answered by leelaram6600
5

am²+bm²-bn²-an²÷m+n

a(m+n)(m+n)+b²(m²-n²) ÷m+n

a(m+n)(m-n)+b(m+n)(m-n)÷m+n)÷m+n

a(m-n)+b(m-n)

(a+b)(m-n)

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