divide and cheak x⁵+x⁴+x³+4x²+5x+3÷x²+x+2
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Let x + 1 is a factor of given polynomial. Now, x + 1 = 0 x = -1 p(-1) = (-1)³ + (-1)² + (-1) + 1 = -1 + 1 - 1 + 1 = 2 - 2 = 0 Therefore, It is confirmed that x + 1 is a
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x²+x⁴+x³+4x²+5x+3
x⁵+x⁴+2x³
- -. -
-x³+4x²+5x+3
-x³-x²-2x
+. +. + _______________
______________
+5²+7x+3
+5x²+5x+10_______
____________________
-. - -
2x-7
verify:-
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