Question

Divide and write the quotient and remainder.
(6x^4 + 3x^2 - 9 + 5x + 5x^3) ÷ (x^2-1)​

Answer 1

Answer:

$\frac{x(x(x(6x+5)+3)+5)-9 }{(x-1)(x+1)}$

Step-by-step explanation:

$\frac{6x^{4}+3x^{2}-9+5x+5x^{3}}{x^{2} -1} =\\\frac{6x^{4}+5x^{3}+3x^{2}+5x-9}{(x-1)(x+1)}=\\\frac{x(6x^{3}+5x^{2} +3x+5)-9 }{(x-1)(x+1)}=\\\frac{x(x(6x^{2}+5x+3)+5)-9 }{(x-1)(x+1)}=\\\frac{x(x(x(6x+5)+3)+5)-9 }{(x-1)(x+1)}$