Question

Divide and write the quotient and the remainder (p2+7p-5)÷(p+3)

Answer 1

$\text{Quotient}=p+4$ and $\text{Remainder}=-17$

Step-by-step explanation:

Expression $(p^2+7p-5)\div(p+3)$

Divide and write the quotient and the remainder of the expression ?

Solution :

We divide $p^2+7p-5$ by $p+3$

$(p^2+7p-5)\div(p+3)=\frac{p^2+7p-5}{p+3}$

$(p^2+7p-5)\div(p+3)=\frac{p^2+3p+4p-5}{p+3}$

$(p^2+7p-5)\div(p+3)=\frac{p(p+3)+4p+12-12-5}{p+3}$

$(p^2+7p-5)\div(p+3)=\frac{p(p+3)+4(p+3)-17}{p+3}$

$(p^2+7p-5)\div(p+3)=\frac{(p+3)(p+4)-17}{p+3}$

$(p^2+7p-5)\div(p+3)=\frac{(p+3)(p+4)}{p+3}-\frac{17}{p+3}$

$(p^2+7p-5)\div(p+3)=p+4-\frac{17}{p+3}$

$(p^2+7p-5)=(p+4)\times (p-3)-17$

We know,

$\text{Dividend}=(\text{Quotient}\times \text{Divisor})+\text{Remainder}$

On comparing,

$\text{Quotient}=p+4$ and $\text{Remainder}=-17$

#Learn more

(p^2+7p-5) divided by (p+3)

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Answer 2

Answer:

Answer=p+4,-17

Answer=p+4,-17

Answer=p+4,-17

Answer=p+4,-17