Divide area of ∆ABC in three equal parts.
[Divide side BC in 3 equal parts]
BishanKDeka:
How can we answer ur question if not give the area and side in the question??
Its a tiangle with side ABC
by making it divide to the centre
by trigonometry
sin^2teta+cos^2teta=1
centroid divides the median into 2:1 ratio
without measurement we can construct median
right
if it is a triangle of side ABC
it's area is 0
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by using centroid we can divide it into three equal half
by using menis bisector BC is divided into 3 half
by using menis bisector BC is divided into 3 half
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