Question

divide as directed : b) 10y (6y+21) ÷ 5 (2y+7)​

Answer 1

Answer:

We first factorise

10y(6y+21)

➡10y[(3×2) y+(3×7)]

$taking \: \: 3 \: \: common$

=10y×3(2y+7)

Dividing,

➡

$\frac{10y(6y + 21)}{5 \times (2y + 7)}$

➡

$\frac{10y \times 3(2y + 7)}{5 \times (2y + 7)}$

$3 \times \frac{10}{5} \times y \times \frac{(2y + 7)}{(2y + 7)}$

$3 \times 2 \times y \times 1$

$= 6y$

Answer 2

Answer:

6y

Step-by-step explanation: