Question

Divide by factorisation.
a. 4(x + 3)2 + 6(x + 3) by x + 3
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Answer 1

Step-by-step explanation:

1. $( 4x \time + 3) { }^{2} + 3 \times (x + 3) \\ x = 3 - 4(x = 3 - 6)(x + 3) \\ x = 1or \: x =3 (x + 3) = 0 \\ x = 1or \: x = 3or \: x - 3$

Answer 2

Step-by-step explanation:

Given:-

4(x + 3)2 + 6(x + 3) and x + 3

To find:-

Divide by factorisation.

4(x + 3)² + 6(x + 3) by x + 3

Solution:-

Given that:-

4(x + 3)² + 6(x + 3) ÷ (x+3)

=>[4(x+3)²+6(x+3)]/(x+3)

=>(x+3)[4(x+3)+6)]/(x+3)

=>4(x+3)+6

=>4x+12+6

=>4x+18

Answer:-

The answer for the given problem = 4x+18