Math, asked by barshabaishalisahu, 16 days ago

divide by long division method and find remainder
(3x²+x-3)÷(2x+)​

Answers

Answered by shauryaveer96
2

Answer:

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Step-by-step explanation:

p(x) = x³ - 3x² + 3x - 2

g(x) = x² - x + 1

★ Dividend = Quotient × Divisor + Remainder

= x³ - 3x² + 3x - 2 = (x - 2) (x² - x + 1) + 0

= x³ - 3x² + 3x - 2 = x(x² - x + 1) - 2(x² - x + 1) + 0

= x³ - 3x² + 3x - 2 = x³ - x² + x - 2x² + 2x - 2 + 0

= x³ - 3x² + 3x - 2 = x³ - 3x² + 3x - 2

Hence, Verified.

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