Math, asked by sanketsalesa1, 1 day ago

divide by method of factorisation= 66(y^4-5y^3-24y^2)➗6y(y-8)

Answers

Answered by nishapradhan358
0

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((y4)-(5•(y3)))-(23•3y2))

((66•——————————————————————————)•y)•(y-8)

6

STEP

2

:

Equation at the end of step

2

:

(((y4)-5y3)-(23•3y2))

((66•—————————————————————)•y)•(y-8)

6

STEP

3

:

y4 - 5y3 - 24y2

Simplify ———————————————

6

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

y4 - 5y3 - 24y2 = y2 • (y2 - 5y - 24)

Trying to factor by splitting the middle term

4.2 Factoring y2 - 5y - 24

The first term is, y2 its coefficient is 1 .

The middle term is, -5y its coefficient is -5 .

The last term, "the constant", is -24

Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -5 .

-24 + 1 = -23

-12 + 2 = -10

-8 + 3 = -5 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 3

y2 - 8y + 3y - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-8)

Add up the last 2 terms, pulling out common factors :

3 • (y-8)

Step-5 : Add up the four terms of step 4 :

(y+3) • (y-8)

Which is the desired factorization

Equation at the end of step

4

:

y2•(y+3)•(y-8)

((66•——————————————)•y)•(y-8)

6

STEP

5

:

Equation at the end of step 5

(11y2 • (y + 3) • (y - 8) • y) • (y - 8)

STEP

6

:

Multiplying exponential expressions :

6.1 y2 multiplied by y1 = y(2 + 1) = y3

Equation at the end of step

6

:

11y3 • (y + 3) • (y - 8) • (y - 8)

STEP

7

:

Multiplying Exponential Expressions:

7.1 Multiply (y-8) by (y-8)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (y-8) and the exponents are :

1 , as (y-8) is the same number as (y-8)1

and 1 , as (y-8) is the same number as (y-8)1

The product is therefore, (y-8)(1+1) = (y-8)2

Final result :

11y3 • (y + 3) • (y - 8)2

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