Divide by synthetic division method(x³-4x²-2x+1)÷(x-3)
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Dividend = (x³-4x²-2x+1 )
Quotient = (x-3)
after performing synthetic division method we get
Remainder = -14
Divisor =(x² −x−5 )
Therefore we can say that:-
(x³-4x²-2x+1) = (x−3−) (x² −x−5) - 14
Ans :- Remainder = -14, Divisor =(x² −x−5 )
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