divide f 9(y) = 3y4 - 8y3 - y2 - 5y - 5 by y -3
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Answer:
16 is the solution.
Step-by-step explanation:
y-3= 0
y= 3
put f(y)= 3
f(y)= 3y^4-8y^3-y^2-5y-5
f(3)= 3(3)^4-8(3)^3-(3)^2-5(3)-5
f(3)= 243-216+9-15-5
f(3)= 27+9-20
f(3)= 16
Therefore, The remainder is 16.
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