Question

Divide i
x²-3x+2
by x-2
​

Answer 1

Answer:

I'm a bit confused on the working to this question. A friend of mine gave me a solution but I dont quite understand why is the working like that.

When P(x) is divided by (x−1) and (x−2), the remainder is 5 and 3 respectively. Find the remainder when it is divided by (x2−3x+2)

And this is the working given to me:

P(x)=Q(x)P(x)+R(x)=Q(x)P(x)+(ax+b)

Remainder Theorem: P(c)=r

P(c)=r=ax+b

P(1)=5=a(1)+b(1)

P(2)=3=a(2)+b(2)

a=−2b=7−2x+7

Why is that when we do simultaneous equation of both these roots and remainder, we get the root function of x2−3x+2 ? I know that (x−1)(x−2)=(x2−3x+2), but I just don't understand the reason of that working.

Answer 2

Answer:

what is your question tell me properly