Divide is into two parts such that three times the first part exceeds one third of the second by 4 the parts are
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Let the 1st part be x.
Therefore, 2nd part=56-x
3 times first part=3*x=3x
1/3rd of 2nd part=(56-x)/3
According to the question,
3x-(56-x)/3=48
or, 9x-56+x=144
or,10x=144+56
or 10x=200 or, x=20
Therefore, 1st part=20 and
2nd part=(56-20)=36.
Ans:The parts are 20 and 36.
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