divide k^x^2-kx+3k^3xby kx
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Answer:
When x
3
+3x
2
−kx+4 is divided by (x−2), the remainder is 2k
∴(x
3
+3x
2
−kx+4)−2 is exactly divisible by (x−2)
⇒x=2 will satisfy the expression [x
3
+3x
2
−kx+4−2k]
⇒ (2)
3
+3(2)
2
−k(2)+4−2k=0
⇒ 8+12−2k+4−2k=0
⇒24−4k=0
⇒ k=
4
24
=6
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