Question

Divide line segment AB of 11cm in the ratio 5:7​

Answer 1

We know that to divide a line segment AB in the ratio m:n

we have to follow the following steps of construction:

1.Draw a line segment AB of a given length by using a ruler.

2. Draw any Ray AX making an acute angle with AB.

3. Along AX mark off (m+n) points A1,A2,A3,….Am,A(m+1),A(m+n) such that AA1=AA2=A(m+n−1)A(m+n)

4.Join BA(m+n).

5. Through the point Am draw a line parallel to A(m+n) by making an angle equal to AA(m+n) which intersects the line segment AB at point P.

The point P so obtained is the required point which divides AB internally in the ratio m:n.

Here, m=5,n=7

Hence,the minimum number of points on the ray AX=5+7=12.

hope it's correct and helps to you...

Answer 2

Step-by-step explanation:

A line segments AB in the ratio 5:7

so,A:B=5:7

now

Mark A+B point at equal distances

so ,we have A=5andB=7