divide m³-6m+7 by m-1
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Let, f( x) = m³ - 6m + 7
g(x) = m - 1
comparing ( m-1) with ( m- a)
m-1 = m- a
a= 1
then,
f( 1) = (1)³ - 6 * 1 + 7
= 1 - 6 + 7
= 2
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