Question

divide (p^2+6p+8) by (p+4)​

Answer 1

${\huge {\underline {\bf {\pink {Answer}}}}}$

= $\displaystyle\frac {{p}^{2}+6p+8}{p+4}$

= $\displaystyle\frac {{p}^{2}+4p+2p+8}{p+4}$

= $\displaystyle\frac {p (p+4)+2 (p+4)}{p+4}$

= $\displaystyle\frac {(p+2)(p+4)}{p+4}$

= p+2

p+2 is the required answer.

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