Math, asked by rahulkennedy, 11 months ago

divide P(x) =2x³+x²+10x-8 by g(x) = x+1​

Answers

Answered by Anonymous
1

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 \huge \mathbb {ANSWER:}

 \small \mathfrak {g(x) = x + 1 = 0} \\ \small \mathfrak {g(x) = x =  - 1}

 \small \mathfrak {p(x) =  {2x}^{3}  +  {x}^{2}  + 10x - 8}

 \small \mathfrak {p( -1 ) = 2 {( - 1)}^{3}  + {( - 1)}^{2}  + 10( - 1) - 8}

 \small \mathfrak {p( - 1) =  - 2 + 1 - 10 - 8}

 \small \mathfrak {p( - 1) =  - 1 - 10 - 8 =  - 19}

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