Question

Divide p(x)=4x^4-3x^3-2x^2+x-7 by g(x)=x-1
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Answer 1

Step-by-step explanation:

Using the remainder theorem, find the remainder when f(x) is divided by g(x) and verify the by actual division :

f(x) = 4x4 – 3x3 – 2x2 + x – 7, g(x) = x – 1

f(x) = 4x4 – 3x3 – 2x2 + x – 7

Put g(x) = 0

⇒ x – 1 = 0 or x = 1

Remainder = f(1)

Now,

f(1) = 4(1)4 – 3(1)3 – 2(1)2 + (1) – 7

= 4 – 3 – 2 + 1 – 7

= -7

Answer 2

Answer:

$\huge{\boxed{\rm{\red{Quotient=4x³+x²-x}}}}$

$\huge{\boxed{\rm{\red{Remainder=-7}}}}$