Question

divide p(x) by g(x) where p(x)=3x^2+x-1 and g(x)=x+1​

Answer 1

$1) \: divide \: p(x) \: by \: g(x) \: where \: \\ p(x)=3x^2+x-1 \: and \: g(x)=x+1 \\ solution. \\ g(x) = x + 1 = 0\\ x = - 1 \\ \\ p(x)=3x^2+x-1 \\ p( - 1) = 3( { - 1)}^{2} + ( - 1) - 1 \\ = 3(1) - 1 - 1 \\ = 3 - 2 \\ = 1 \: \: is \: the \: remainder...$