Math, asked by peeyushbisht2006, 1 month ago

Divide p(x) by g(x), where p(x) =7x+5x^2+3 and g(x)-x+1​

Answers

Answered by laxmanpawar1167
0

Answer:

Given:-

p(x)=x

3

−3x

2

+5x−3

g(x)=x

2

−2

p(x)÷g(x)

(x

3

−3x

2

+5x−3)÷(x

2

−2)

x

2

−2

x

3

−3x

2

+5x−3

=(x−3)+

(x

2

−2)

(7x−9)

Quotient =(x−3)

Remainder =(7x−9)

Answered by devanshu1234321
34

QUESTION:-

Divide p(x) by g(x), where p(x) =7x+5x²+3 and g(x)=x+1​

EXPLANATION:-

To divide p(x) by g(x) we will use remainder theorem:-

So,

x+1=0

x=-1

So the remainder will be p(-1)

Let's find the value of p(-1):-

p(-1)=7(-1)+5(-1)²+3

p(-1)=-7+5+3

p(-1)=1

So the remainder when p(-1) is divided by g(x) is 1

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