Math, asked by Soumaydadwal, 5 days ago

Divide p(x) by g(x),where p(x),where p(x)=3x^2+3x-1 and g(x)=1+x​

Answers

Answered by amritapokhrel62
2

Answer:

Solution:-

Here

p(X) = 3x²+ 3x - 1

comparing (x+1) with (x-a)

X+1 = x- a

a= -1

then,

p(a) = 3x² + 3x -1

p(-1)= 3* (-1)² + 3*(-1) - 1

= 3* 1 + 3 * (-1) - 1

= -1

Answered by madhurimag00
1

Answer:

The quotient that we get by dividing p(x) by g(x) is 3x and the remainder is -1.

Step-by-step explanation:

We have been given two polynomials p(x) and g(x), we need to divide p(x)  by g(x), twe can divide two polynomials by the simple division method with just a few rules in mind.

p(x)=3x^{2} +3x-1

g(x)=1+x

The division will be done as follows:

x+1 ) 3x^{2} +3x-1 ( 3x

       3x^{2} +3x

     (-)     (-)

______________

                  -1

Thus the quotient that we get from dividing p(x) by g(x) is 3x and the remainder is -1.

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