Divide P(X) by Q(X) and find the quotient and remainder.
P(X)=x³+9x²+27x + 27 and Q(X)=x+3
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Answer:
Given p(x)=x
3 +1 x+1x 3 +1 = x+1(x+1)(x 2 −x+1) = x 2 −x+1
Therefore, p(x) is divisible by x+1.
Hence, the remainder is zero.
Answered by
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Step-by-step explanation:
2x² + 5x - 7y and 3x² + 9x - 8y
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