divide p(x) by q(x). p(x)=x^3+(31/6)x^2-2x+4,q(x)=1+(3x/2) find the remainder
Answers
Answered by
1
Answer:
The zero of g(x)=1−2x is x=
2
1
Now, by remainder theorem the remainder should be f(
2
1
)
∴f(
2
1
)=(
2
1
)
3
−6(
2
1
)
2
+2(
2
1
)−4
=(
8
1
)−6(
4
1
)+1−4
=(
8
1
)−(
4
6
)−3
=
8
1−12−24
=−
8
35
Answered by
0
Answer:
p(x)=x^{3}+\frac{31}{6}x^{2}-2x+4,q(x)=1+\frac{3x}{2
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