Math, asked by CasySmith, 7 hours ago

Divide p(x) = x^3 + 4x^2 + 1 by (gx) = x + 1

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Answers

Answered by bhavansri41056
1

Answer:

The division of p(x)=x

3

+4x

2

−5x+6 by g(x)=x+1 is as shown above:

Now we know that the division algorithm states that:

Dividend=(Divisor×quotient)+Remainder

Here, the dividend is x

3

+4x

2

−5x+6, the divisor is x+1, the quotient is x

2

+3x−8 and the remainder is 14, therefore,

x

3

+4x

2

−5x+6=[(x+1)(x

2

+3x−8)]+14

⇒x

3

+4x

2

−5x+6=[x(x

2

+3x−8)+1(x

2

+3x−8)]+14

⇒x

3

+4x

2

−5x+6=x

3

+3x

2

−8x+x

2

+3x−8+14

⇒x

3

+4x

2

−5x+6=x

3

+3x

2

+x

2

−8x+3x−8+14

⇒x

3

+4x

2

−5x+6=x

3

+4x

2

−5x+6

Hence, the division algorithm is verified.

Answered by guriyasinghpatna
1

Answer:

(gx) =x+1=0

x=-1

x3+4x2+1

(-1)3+4(-1)2+1

-1+4+1

answer is 4

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