Question

Divide p(x) = x^3 + 4x^2 + 1 by (gx) = x + 1
Please help me with this question.
Step by step explanation.

Answer 1

Answer:

x

3

−4x

2

+5x−2

=

x

2

−2x+1

solution

Answer 2

Question:-

$\tt Divide ~p(x) ~= ~x^3 + 4x^2 + 1 ~by ~(gx)~ = x + 1$

Solution:-

$\begin{array}{ c c c } x+1 & \bigg) \: \: x^3+4x^2+0x+1 \: \: \bigg( & x^2+3x-3 \\ & \underline{ {x}^{3} + {x}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } & \\ & 3 {x}^{2} + 0x & \\ & \underline{ 3 {x}^{2} + 3x}& \\ & \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 3x + 1 \\& \: \: \: \: \: \: \: \underline{ \: \: \: \: \: \: \: \: - 3x - 3} \\ & \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4\end{array}$

Quotient= $\sf x^2+3x-3$

Remainder = 4