Question

divide polynomial 2x^4-4x cube-3x-1 by (x+1) and verify the remainder.​

Answer 1

     

$2x^4-4x ^3-3x-1 \\ \\ 2x^4+2x^3-6x^3-6x^2+6x^2+6x-9x-9+8 \\ \\ 2x^3(x+1)-6x^2(x+1)+6x(x+1)-9(x+1)+8 \\ \\ (x+1)(2x^3-6x^2+6x-9)+\bold{8}$

$\therefore\ \sf{The remainder is \bold{8}. } \\ \\ \\ \sf{Plz mark it as the brainliest. \\ \\ \\ Thank you. :-)}$