divide q2-4q-32 by q+4
Answers
Answer:
q2+4q-32=0
Two solutions were found :
q = 4
q = -8
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "q2" was replaced by "q^2".
Step by step solution :
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring q2+4q-32
The first term is, q2 its coefficient is 1 .
The middle term is, +4q its coefficient is 4 .
The last term, "the constant", is -32
Step-1 : Multiply the coefficient of the first term by the constant 1 • -32 = -32
Step-2 : Find two factors of -32 whose sum equals the coefficient of the middle term, which is 4 .
-32 + 1 = -31
-16 + 2 = -14
-8 + 4 = -4
-4 + 8 = 4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 8
q2 - 4q + 8q - 32
Step-4 : Add up the first 2 terms, pulling out like factors :
q • (q-4)
Add up the last 2 terms, pulling out common factors :
8 • (q-4)
Step-5 : Add up the four terms of step 4 :
(q+8) • (q-4)
Which is the desired factorization
Equation at the end of step 1 :
(q + 8) • (q - 4) = 0
Step-by-step explanation: