Math, asked by shourya3364, 10 months ago


divide Rs 100 between A, B, and C so that
B may have Rs 8 more than A and C rs 14
more than B​

Answers

Answered by mondalankan41
0

Answer:

Money with B= Rs.32

Step-by-step explanation:

Let the money with B be 'x'

Money with A= x-8

Money with C = 14+x

x+x+14+x-8=100

3(x)=96

x=32

Money with A = 32-8 = Rs.24

Money with C = Rs.46

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