Math, asked by sampathyerramsetty, 4 months ago

Divide Rs. 1080 into two parts such that if the first be lent at
6% for 5 years and second be lent at 10% for 4 years
, the
interest may be in the ratio 3 : 5.​

Answers

Answered by bhagyashreechowdhury
0

Given:

Divide Rs. 1080 into two parts such that if the first be lent at 6% for 5 years and the second be lent at 10% for 4 years, the interest may be in the ratio 3 : 5.​

To find:

The two parts

Solution:

We know,

\boxed{\bold{Simple \:Interest = \frac{P \times R \times T}{100} }}

For the first part interest:

The rate of interest, R = 6%

The no. of years, T = 5 years

Let "x" be the sum of money lent.

Simple \:Interest = \frac{x \times 6 \times 5}{100} = \frac{30x}{100}

For the second part interest:

The rate of interest, R = 10%

The no. of years, T = 4 years

Let "(1080 - x)" be the sum of money lent.

Simple \:Interest = \frac{(1080 - x) \times 10 \times 4}{100} = \frac{40(1080 - x)}{100}

Now, as given in the question, we can form the equation as:

\frac{First\:part}{Second\:part} = \frac{3}{5}

\implies \frac{ \frac{30x}{100}}{ \frac{40(1080 - x)}{100}}  = \frac{3}{5}

\implies \frac{ 30x}{ 40(1080 - x)}  = \frac{3}{5}

\implies 150x = 120(1080 - x)

\implies 150x = 129600 - 120x

\implies 270x = 129600

\implies \bold{x = 480}

\bold{1080 - x} = 1080 - 480 = \bold{600}

Thus,

\boxed{\bold{1st \:part \:\rightarrow \underline{Rs.\: 480}}}\\\\\boxed{\bold{2nd \:part \:\rightarrow \underline{Rs.\: 600}}}

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